[Python-talk] Calling functions with variable number of arguments
bruce.labitt at autoliv.com
bruce.labitt at autoliv.com
Tue Sep 1 13:05:03 EDT 2009
Say one has three functions, function 1 has one input argument, function 2
has 2 input arguments and function 3 has no input arguments.
I have made a function list, and an argument list
def func1(n):
print 'Function '+str(n)+' ran'
def func2( n, a ):
print 'Function '+str(n)+' ran '+str(a)+'times'
def func3:
print 'Function 3 ran'
funclist = [func1, func2, func3]
arglist = [ a, (b,c), None ]
I'd like to execute something like this (which does not work)
for item, arg in zip( funclist, arglist ):
item( arg )
If I run this, it dies on the call to func2, giving a TypeError Exception.
So I use *arg. This only works for func2, but fails for func1 with
TypeError because "argument after * must be a sequence"
I can get func1 & func3 to work if I modify the function func3 from above
to
def func3(a):
print 'Function 3 ran'
So is there a way to get all three functions to work using a similar (or
any) construction?
Thanks!
Bruce
Bruce Labitt
Autoliv Electronics
1011B Pawtucket Blvd, PO Box 1858
Lowell, MA 01853
Email: bruce.labitt at autoliv.com.
Tel: (978) 674-6526
Fax: (978) 674-6581
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